C)
g(θ) = 1 - cos^θ + √3
Recall, Sin^2θ = 1 - Cos^2θ. Thus,
g(θ) = Sin^2θ + √3
g(θ) = f(θ)
Sin^2θ + √3 = 2Sinθ + √3
Sin^2θ = 2Sinθ + √3 - √3
Sin^2θ = 2Sinθ
Sin^2θ - 2Sinθ = 0
By factoring Sinθ, we have
Sinθ(Sinθ - 2) = 0
Sinθ = 0 or Sinθ - 2 =
Sinθ = 0 or Sin