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The bases are regular hexagons. The area of each is about 416 om. Find the sum of their areas (SHOW ALL WORK)

The bases are regular hexagons. The area of each is about 416 om. Find the sum of-example-1

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The image has two(2) hexagons as the top and base of the figure, and six(6) rectangular blocks by the sides.


\begin{gathered} \text{The area of the base is 41.6 cm}^2 \\ \text{Thus, the area of the 2 hexagons at the top and the base is 2}*41.6=83.2cm^2 \end{gathered}
\begin{gathered} \text{The dimension of one of the rectangular blocks 4cm by 9cm.} \\ \text{Thus, the area of the rectangular block is 4}*9=36cm^2 \end{gathered}

For six(6) rectangular blocks, the area becomes:


\begin{gathered} A=6*36 \\ A=216cm^2 \end{gathered}

Hence, sum of their areas is 83.2 + 216 = 299.2 square centimeter.

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