Question

An object with a mass of 2.6 kg experiences an applied force of 6.9 N and a frictional force of 1.8 N. What is it the resulting acceleration?

Answer 1

`\begin{equation*} 1.96\text{ }m\/s^2 \end{equation*}`

Step-by-step explanation

We want to find the resulting acceleration of the object.

To do this, we apply the formula for the net force acting on the object:

`F_(net)=ma`

where Fnet = net/total force acting on the object

m = mass

a = acceleration

The net force is the sum of the applied force and the frictional force (which is negative):

`\begin{gathered} F_(net)=F+(-F_r) \\ \\ F_(net)=F-F_r \end{gathered}`

Substitute that into the equation for net force and solve for a:

`\begin{gathered} F-F_r=ma \\ \\ a=(F-F_r)/(m) \\ \\ a=(6.9-1.8)/(2.6) \\ \\ a=1.96\text{ }m\/s^2 \end{gathered}`

That is the acceleration.