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A(x) = 5x^1/5-2Find the inverse

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For this type of question, first, we set the following equation:


y=5x^{(1)/(5)}-2

Then, we exchange y and x:


x=5y^{(1)/(5)}-2

Now, we solve the above equation for y:


\begin{gathered} x+2=5y^{(1)/(5)} \\ y^{(1)/(5)}=(x+2)/(5) \\ y=((x+2)/(5))^5 \end{gathered}

Answer:


A^(-1)(x)=((x+2)/(5))^5

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