We will proceed as follows:
a)
![16x^2+25y^2=400](https://img.qammunity.org/2023/formulas/mathematics/college/1euoj2fggynhtizdak7qtebbiuu75kvd29.png)
From this, we can see that the x-intercepts are located at (-5, 0) & (5, 0).
The y-intercepts are located at (0,4) & (0, -4).
The domain is [-5, 5] and their range is [-4, 4]
b)
![25x^2+16y^2=400](https://img.qammunity.org/2023/formulas/mathematics/college/pk0me612t35psjs47z2yg7kuu0qdua6al0.png)
From this, we can see that the x-intercepts are located at (-4, 0) & (4, 0).
The y-intercepts are located at (0, 5) & (0, -5).
The domain is [-4, 4], and the range [-5, 5].
***
For ellipsis, we find their x & y-intercepts as follows:
*Since they are written in the form:
![(ax)^2+(by)^2=c^2](https://img.qammunity.org/2023/formulas/mathematics/college/3hd4c2cgq0j23evec1o0injdybhsw0omu3.png)
The value a that accompanies x will give as a solution the y-component of the y-intercept, and the b value that accompanies the y-component gives the x-component of the x-intercept.
*The domain is given by greatest and lowest x-values [The extremes of the shape] and the range is given by the greatest and lowest y-values.