Question

Find y if the line through (5,2) and (-3,y) has a slope m= -11/8.

Answer 1

`\begin{gathered} \text{slope, m = }(y_2-y_1)/(x_2-x_1) \\ \\ m=-(11)/(8),x_1=5,y_1=2,x_2=-3,y_2=y \end{gathered}`

Substituting these values, we have

`\begin{gathered} -(11)/(8)=\text{ }(y-2)/(-3-5) \\ \\ -(11)/(8)=(y-2)/(-8) \\ 8(y-2)=\text{ -8 x -11} \\ 8y-16=88 \\ 8y=88+16 \\ 8y=104 \\ y=(104)/(8) \\ y=13 \end{gathered}`