Question

How do you solve 4√-6 x 2√-3?

Answer 1

`4\sqrt[]{-6}*2\sqrt[]{-3}=(4*2)(\sqrt[]{-6})(\sqrt[]{-3})=8\sqrt[]{-6}\sqrt[]{-3}`
`=8(\sqrt[]{(-1)(6)})(\sqrt[]{(-1)(3)})=8(i\sqrt[]{6})(i\sqrt[]{3})`
`=8i^2(\sqrt[]{6})(\sqrt[]{3})=-8(\sqrt[]{(3)(2)})(\sqrt[]{3})=-8(\sqrt[]{3}^2)(\sqrt[]{2})=-24\sqrt[]{2}`

then the answer will be -24√2