Question

what is the velocity of the student?how much kinetic energy does the student have while sprinting?what is the mechanical energy of the student?

Answer 1

Given data:

* The mass of the student is m = 65 kg.

* The distance covered by the student is d = 100 m.

* The time taken by the student to cover the distance is t = 12 seconds.

Solution:

(a). The velocity of the student is,

`\begin{gathered} v=(d)/(t) \\ v=(100)/(12) \\ v=8.33\text{ m/s} \end{gathered}`

Thus, the velocity of the student is 8.33 meters per second.

(b). The kinetic energy of the student is,

`\begin{gathered} K=(1)/(2)mv^2 \\ K=(1)/(2)*65*(8.33)^2 \\ K=2255.14\text{ J} \end{gathered}`

Thus, the kinetic energy of the student is 2255.14 J.

(c). The mechanical energy of the student is the energy acquired by the student during its motion.

Thus, the mechanical energy of the student is 2255.14 J.