Question

I'm stuck on this problem trying to figure it out.

Answer 1

Given:

The confidence level is, c = 95% = 0.95.

The value of standard deviation is, σ = 3.6.

The value of sample size is, n = 100.

The objective is to find the margin of error.

Step-by-step explanation:

The general formula to find the margin of error is,

`\text{E}=z_c*\frac{\sigma}{\sqrt[]{n}}\text{ .. . . . (1)}`

From the critical value table, the value z for c = 95% is,

`z_c=1.96`

To find E:

Now, substitute the obtained values in equation (1).

`\begin{gathered} \text{E}=1.96*\frac{3.6}{\sqrt[]{100}} \\ =1.96*(3.6)/(10) \\ \approx0.706 \end{gathered}`

Hence,