In this case, we will use the z-score to compare each student to the distribution corresponding to each career.
a) Evan took a test in Art History and he earned a 74.1.
The scores in Art History have a mean of 70.6 and a standard deviation of 8.9.
We can then calculate the corresponding z-score for this result as:
![z=(X-\mu)/(\sigma)=(74.1-70.6)/(8.9)=(3.5)/(8.9)\approx0.3933](https://img.qammunity.org/2023/formulas/mathematics/college/f70snm27dow2xhkiftqx9z3zeuclpg9yp1.png)
b) Jeff took a test in Social Studies and earned a 62.7.
The scores in Social Studies have a mean of 62.5 and a standard deviation of 9.5.
Then, we can calculate the z-score as:
![z=(X-\mu)/(\sigma)=(62.7-62.5)/(9.5)=(0.2)/(9.5)\approx0.021](https://img.qammunity.org/2023/formulas/mathematics/college/fsvigyz8587l0bbsu6lgxejferxufb5s6t.png)