Question

What is the effective resistance (in Ω) of a car's starter motor when 147 A flows through it as the car battery applies 11.3 V to the motor?

Answer 1

Given:

The current flowing through the motor is: I = 147 A

The voltage applied to the motor is: V = 11.3 v

To find:

The effective resistance of the car's motor.

Step-by-step explanation:

The relation between the voltage V, current I, and the resistance R is given by Ohm's law. The expression for Ohm's law is:

`V=IR`

Rearranging the above equation, we get:

`R=(V)/(I)`

Substituting the values in the above equation, we get:

`\begin{gathered} R=\frac{11.3\text{ v}}{147\text{ A}} \\ \\ R=0.0768\text{ }\Omega \\ \\ R\approx0.077\text{ }\Omega \end{gathered}`

Final answer:

The effective resistance of the car's motor is 0.077 Ω.