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Marcus can walk 1 mile to the library in the same time he can bicycle 2.5 miles to the sporting goods store. His speed on the bicycle is 6 ml/h fasterthan his walking speed. What is his speed walking?13 ml/h10 ml/h4 mi/h5.2 ml/h

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Answer:

4 miles per hour

Step-by-step explanation:

Let s represent Marcus' walking speed.

Therefore, bicycle speed = s + 6.

The relationship between speed(s), distance(d) and time(t) can be expressed mathematically as shown below;


\begin{gathered} s=(d)/(t) \\ t=(d)/(s) \end{gathered}

From the question, we can see that walking time = bicycle time.

So we'll have;


\begin{gathered} \text{walk time = bicycle time} \\ (1)/(s)=(2.5)/(s+6)_{} \\ s+6=2.5s \\ 2.5s-s=6 \\ 1.5s=6 \\ s=(6)/(1.5) \\ s=4 \end{gathered}

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