34.6k views
2 votes
An exponential relationship y = f(x) has a l-unit percent change of 12% with f(0) = 28.i. Define a formula for function f modeling this relationship. Be sure to use function notation, and be sure to use the correct function name.

1 Answer

6 votes

f(x)=28*(1.12)^x

The percent change is 12%, meaning after each interval x the new value is 112% times the previous value. This can be expressed as (for x = 1)


\text{new value=28}*(112)/(100)

when x = 2 the above value becomes the "previous value" and therefore, the new value will be


\text{new value =(28}*(112)/(100))*(112)/(100)

when the above becomes the previous value the new value then will be


\text{new value =((28}*(112)/(100))*(112)/(100))*(112)/(100)

and so on until we have x number of 122/100 =1.12 terms. Then the new value for any x can be written as


\text{new value for any x=28(}(112)/(100))^x

or


f(x)=28(1.12)^x

User Willi Ballenthin
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories