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Given: vu=st, sv=tu prove vx=xt

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Given an image of a parallelogram

Both pairs of opposite sides are parallel.

Both pairs of opposite sides are congruent.

Diagonals bisect each other, VT= SU (diagonal line)

SU and VT is a bisector line hence the line VX = XT since the diagonal bisect each other

Hence the line VX = XT since the diagonal bisect each other at X

Given: vu=st, sv=tu prove vx=xt-example-1
User David Rutten
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