Hello there. To solve this question, we have to remember how to graph a function.
First, remember that the logarithm in any base is an injective function (one-to-one).
We have to find its key-features before graphing it.
These key-features includes: x-intercept, y-intercept (if it exists), its vertical asymptote.
Okay. To find the x-intercept, set the function equal to zero:

Adding 1 on both sides, we get

Apply the property:

Hence we have

So the x-intercept happens at x = 3.
To determine whether or not it has an y-intercept, we check if the limit as x goes to zero from both sides exists and are equal:

In this case, this means we cannot evaluate this function at x = 0, so it doesn't have y-intercept(s).
Next, to determine its vertical asymptote, we check the value of x for which the argument goes to zero, that is

Therefore it has a vertical asymptote at x = 0.
The graph is then given by:
This is a sketch of the graph of the function.
The final answer to this question is contained in the last option.