Question

(4,-8), (-3, 1) in slope intercept form please and thank you

Answer 1

To find the slope we need to apply:

`\text{slope = m=}((y_2-y_1))/((x_2-x_1))`

We have two points and we have:

`\begin{gathered} (x_1,y_1)=(4,-8) \\ (x_2,y_2)=(-3,1) \\ \end{gathered}`

Now we find m,

`\begin{gathered} \text{m=}((y_2-y_1))/((x_2-x_1))=((1-(-8)))/((-3-4))=(1+8)/(-7)=(9)/(-7); \\ m=(-9)/(7) \end{gathered}`

After that, we apply the general equation of the line:

`\begin{gathered} (y-y_1)=m(x-x_1);_{}_{} \\ we\text{ replace the values for m,} \\ x_1=4 \\ y_1=-8 \\ (y-(-8))=(-9)/(7)(x-4); \\ y+8=(-9)/(7)x+(36)/(7) \\ \\ y=(-9)/(7)x+(36)/(7)-8 \\ y=(-9)/(7)x-(20)/(7) \end{gathered}`

and from that, the intercept will be:

`b=-(20)/(7)`