If vector u = (5,-7), then 6u = (5*6, -7*6) = (30, -42)
If vector v = (-11, 3), then 2v = (-11*2, 3*2) = (-22, 6)
Therefore, 2v - 6u = (-22 - 30, 6 - (-42)) = (-52, 48)
||v|| si the length of vector v. If v = (x, y), then
![\mleft\Vert v\mleft\Vert=\mright?\mright?\sqrt[]{x^2+y^2}](https://img.qammunity.org/2023/formulas/mathematics/college/6ns4boqu3zxv3xrhb0ky9vgvos5negtsbv.png)
Replacing with the components of 2v - 6u,we get:
![\mleft\Vert2v-6u\mleft\Vert=\sqrt[]{(-52)^2+48^2}\mright?=\sqrt[]{2704+2304}=\sqrt[]{5008}=70.767\mright?](https://img.qammunity.org/2023/formulas/mathematics/college/thztkfns6kohrlz1ihwz7nxgjiq8q1opaw.png)