Question

A closed container has 3.06.10to the power of 23 atoms of a gas each atoms of the gas weight

Answer 1

Given: The container contained

`\begin{gathered} 3.06*10^(23)atoms \\ each\text{ atom weighs} \\ 1.67*10^(-24) \end{gathered}`

To Determine: The total mass in grams of all the atoms

Solution

`\begin{gathered} If \\ 1atom=1.67*10^(-24) \end{gathered}`

Then

`3.06*10^(23)atoms=3.06*10^(23)*1.67*10^(-24)`
`\begin{gathered} 3.06*10^(23)=3.06*1.67*10^(23)*10^(-24) \\ =5.1102*10^(23-24) \\ =5.1102*10^(-1)grams \end{gathered}`
`=0.51grams`

Hence, the total mass in grams of all the atoms is 0.51 grams because (3.06 x 10²³) x (1.67 x 10⁻²⁴), OPTION B