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Solve the quadratic equation below.3(x-2)^2=12

User Harinder
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1 Answer

5 votes

Solving the quadratic equation, we have:


\begin{gathered} 3(x-2)^2=12 \\ (x-2)^2=(12)/(3) \\ (x-2)^2=4 \\ \sqrt[]{(x-2)^2}=\sqrt[]{4} \\ \begin{cases}x-2=2\to x=4 \\ x-2=-2\to x=0\end{cases} \end{gathered}

So the solution for this quadratic equation is x = 0 or x = 4.

User Snksnk
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