We will solve as follows:
The shape is a rectangle triangle with a side of 30 and other side of 12. We calculate the hypotenuse:
![h=\sqrt[]{12^2+30^2}\Rightarrow h=6\sqrt[]{29}](https://img.qammunity.org/2023/formulas/mathematics/college/aesj2h4ur9myumsqcooh0m1mmwl5bfof56.png)
Now, using the law of sines, we solve:
![\frac{6\sqrt[]{29}}{\sin(90)}=(30)/(\sin (\alpha))](https://img.qammunity.org/2023/formulas/mathematics/college/f0knhgua0lrtaz40yikahgsxl3llz9qinf.png)
Now we solve for alpha:
![\Rightarrow\sin (\alpha)=\frac{30\sin(90)}{6\sqrt[]{29}}\Rightarrow\alpha=\sin ^(-1)(\frac{30\sin(90)}{6\sqrt[]{29}})](https://img.qammunity.org/2023/formulas/mathematics/college/sfaxom78aa488wkq9fwaa1dp9paw3hpj2m.png)
From this we will have that the angle of elevation when she looks is of aproximately 68.2°.