Question

The perimeter of a rectangular painting is 302 centimeters. If the width of the painting is 68 centimeters, what is it’s length?

Answer 1

The perimeter of the rectangle is given as 302.

It is given that the width is 68.

Recal the formula for perimeter of a rectagle:

`P=2(l+w)`

Substituting values gives:

`302=2(l+68)`

Solve the equation for l.

`\begin{gathered} (302)/(2)=l+68 \\ 151=l+68 \\ l=151-68 \\ l=83 \end{gathered}`

Therefore the length of the rectangle is 83