hello
the question given is a right angle triangle and we have to use trigonometric ratios to solve this
SOHCAHTOA
![\begin{gathered} \text{SOH}=\sin \theta=(opposite)/(hypothenus) \\ \text{CAH}=\cos \theta=(adjacent)/(hypoth\\u ens) \\ \text{TOA}=\tan \theta=(opposite)/(adjacent) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/r2az8a3ytmbalkuie9kczvkng33oeyj0tr.png)
now we can bring in the triangle and see
now we can take each trigonometric ratio and check which one is incorrect
![\begin{gathered} \sin A=\frac{\text{opp}}{\text{hyp}} \\ \sin A=(8)/(10)=(4)/(5) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/7lxy00tjw4m4nr4xmdki5l7jxcvs34lecp.png)
![\text{cosA}=\frac{\text{adj}}{\text{hyp}}=(8)/(10)=(4)/(5)](https://img.qammunity.org/2023/formulas/mathematics/college/ufxche556rteu3b120odeuk7p495mgfdny.png)
![\sin B=(opp)/(hyp)=(6)/(10)=(3)/(5)](https://img.qammunity.org/2023/formulas/mathematics/college/2x6q3h47n1qnxqgetomrhiz7oizwx4b803.png)
![\cos B=\frac{\text{adj}}{\text{hyp}}=(8)/(10)=(4)/(5)](https://img.qammunity.org/2023/formulas/mathematics/college/667a8sos90pm8gpcj0jnk2838d0v27txwc.png)
from the calculations above, option A is correct
option B is incorrect
option C is incorrect
option D is correct