We will find the linear equation of the graph shown. For doing so, we will find the slope with the formula:
![m=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/78uaqhwt0aws3qfwxigaftpihnmb1gzxtp.png)
Where (x₁, y₁) and (x₂, y₂) are the coordinates of two points of the line.
In this line, we see that the graph passes through the points:
![(6,0)\text{ and }(0,3)](https://img.qammunity.org/2023/formulas/mathematics/college/9y8rj3op63lzfcvfesqxt48cmeg2q8e4zv.png)
This gives us the y-intercept, as the function passes for y=3, when x=0. The slope is given by:
![m=(3-0)/(0-6)=(3)/(-6)=-(1)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/24bhwghc7y217wb156q3jubcngu3nsfhkz.png)
Hence, the linear equation of the function shown is:
![y=-(1)/(2)x+3](https://img.qammunity.org/2023/formulas/mathematics/college/p2r901jr25mmbe7b11ssg2n99n2dskoqmn.png)