The sample standard deviation is calculated as:
![s=\sqrt{\frac{\sum(x_i-\bar{x})^2}{n-1}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/pkbsohlxa1qohlum670qn5f63szchpxqt1.png)
Where:
xi is the value of each sample
x(bar) is the mean of the sample
n is the number of samples
The dataset is 6, 7, 13, 11, 13
First, calculate the mean:
![\bar{x}=(6+7+13+11+13)/(5)=(50)/(5)=10](https://img.qammunity.org/2023/formulas/mathematics/high-school/nd1jvh8q2vpadklcc7gfwo6gn4apvoedir.png)
Now compute the differences between each data and the mean:
6 - 10 = -4
7 - 10 = -3
13 - 10 = 3
11 - 10 = 1
13 - 10 = 3
Square each result above:
(6 - 10)^2 = 16
(7 - 10)^2 = 9
(13 - 10)^2 = 9
(11 - 10)^2 = 1
(13 - 10) = 9
Sum the results above:
16 + 9 + 9 + 1 + 9 = 44
Calculate the standard deviation:
![s=\sqrt{(44)/(4)}=√(11)=3.32](https://img.qammunity.org/2023/formulas/mathematics/high-school/m0lqkigd4n3nfdropjykpn2c1flwwu31iz.png)
The standard deviation is 3.32