Question

A group of people were asked if they had run a red light in the last year. 273 responded "yes", and 101 responded "no".Find the probability that if a person is chosen at random, they have run a red light in the last year. Give your answer as a fraction or decimal accurate to at least 3 decimal places

Answer 1

There are 273 + 101 = 374 people total.

Out of those 374, there are 273 who said "yes" to running a red light.

So the probability is approximately 273/374

`\begin{gathered} Pr(runs\text{ a red light\rparen = }(273)/(374)=0.7299 \\ \approx0.730\text{ \lparen3d.p\rparen} \end{gathered}`

Hence the probability that they have run a red light in the last year is approximately = 0.730