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Find the slope of the line that passes through (2,6) and (-7,8)

User Puggan Se
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\text{slope}=-(2)/(9)

Step-by-step explanation

Step 1

when you have two points of a line, P1, and P2, you can find the slope using:


\begin{gathered} \text{slope}=(\Delta y)/(\Delta x)=(y_2-y_1)/(x_2-x_1) \\ \text{where} \\ P1(x_1,y_1) \\ P2(x_2,y_2) \end{gathered}

Let

P1(2,6)

P2(-7,8)

Step 2

replace


\begin{gathered} \text{slope}=(\Delta y)/(\Delta x)=(y_2-y_1)/(x_2-x_1) \\ \text{slope}=(8-6)/(-7-2)=(2)/(-9)=-(2)/(9) \end{gathered}

I hope this helps you

User Berak
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