We are given the graph of a line. We notice that the line goes through the origin, therefore, the equation must be of the following form:
![y=mx](https://img.qammunity.org/2023/formulas/mathematics/college/vvo9hzn6fevndvhvtnqpmjhwggazm06a.png)
Replacing the point (4, 100) we get:
![100=m(4)](https://img.qammunity.org/2023/formulas/mathematics/college/5648oiso8ecjuhzh11071s0xijh660htxg.png)
Solving for "m" by dividing by 4 to both sides:
![(100)/(4)=m](https://img.qammunity.org/2023/formulas/mathematics/college/siz4hhw2gp04br7ti2g84j304k4cei52y0.png)
Solving the operation:
![25=m](https://img.qammunity.org/2023/formulas/mathematics/college/orb0nywj6brlp3d3skwela3ryleiyzld5r.png)
Replacing the value of "m":
![y=25x](https://img.qammunity.org/2023/formulas/mathematics/college/dgd6d6m7tm18q33rhkkf9kimtkv7ejmrq9.png)
Replacing the value of x = 12:
![y=25(12)](https://img.qammunity.org/2023/formulas/mathematics/college/fdmz3jrv1ad1skc1dqh2dyffja0uvghm7c.png)
Solving the operation:
![y=300](https://img.qammunity.org/2023/formulas/mathematics/college/yu2x8hcu5p330urkt7z6t4qo6ah0edhkvt.png)
Now for the graph, we use the same general form:
![y_2=mx](https://img.qammunity.org/2023/formulas/mathematics/college/csi16yp5ido3ej80os4jih0bcmukxwzckv.png)
We replace the point (2, 60) we get:
![60=m(2)](https://img.qammunity.org/2023/formulas/mathematics/college/p7puc9b6j54ga43xzb2mg4fc982na8y3sv.png)
Solving for "m":
![\begin{gathered} (60)/(2)=m \\ 30=m \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/mm2sqv95hnxwfv03xxciuyiv6l3ibjq11b.png)
Replacing the value of "m":
![y_2=30x](https://img.qammunity.org/2023/formulas/mathematics/college/ifakqo7u97o4oi68bdxn6rkzsn6llm91al.png)
Replacing x = 12:
![\begin{gathered} y_2=(30)(12) \\ y_2=360 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/h6j1n9msf02g59ha1c5mgh9dmrfs6omj53.png)
Therefore, the value of "y" is 60 more on the graph in comparison with the table.