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If f x equals 3x 2 + 4 mg equals 1 - x 2 - x 1 (g o f ) (x)

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The function f(x) = 3x^2 + 4 is given. To solve for

[g of f] (x), you now have;


\begin{gathered} \lbrack\text{g of x\rbrack(x);} \\ g(x)=(1)/((x^2-x)) \\ \lbrack g\text{ of x\rbrack(x)=}(1)/((3x^2+4)^2-(3x^2+4)) \\ =(1)/((9x^4+12x^2+12x^2+16)-3x^2+4) \\ =(1)/(9x^4+21x^2+20) \end{gathered}

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