We will have the following:
1.
*Longitudinal wave: The oscillations where the particles are displaced are parallel to the wave direction.
*Transverse wave: The oscillations where the particles are displaced are perpendicular to the wave direction.
2. If a wave has a period of 0.03s, then its frequency is:
![f=(1)/(T)\Rightarrow f=(1)/(0.03)\Rightarrow f=(100)/(3)Hz](https://img.qammunity.org/2023/formulas/physics/college/dhc7kdtzuq6ea9cfk5vp173e8e6y3ja89z.png)
So, its frequency will be of 100/3 Hertz.
3. We will have that the periods in questions are 0.03s & 0.25s. And their frequencies are:
![\begin{gathered} f_1=(1)/(0.03s)\Rightarrow f_1=(100)/(3)Hz \\ \\ f_2=(1)/(0.25s)\Rightarrow f_2=4Hz \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/ra1jq8gvpsg2cggsc8fdjos98zy0rw4nrs.png)
From this we can see that the greater frequency numerically will be 4Hertz, and that one belongs to the wave with a period of 0.25s.
4. We will have that the velocity is:
![v=\lambda\ast f\Rightarrow v=(4.5m)((1)/(0.007s))](https://img.qammunity.org/2023/formulas/physics/college/4t9nusqw5h9k5xlr69evy8ljwlm2r8os4z.png)
![\Rightarrow v=(4500)/(7)m/s\Rightarrow v\approx642.9m/s](https://img.qammunity.org/2023/formulas/physics/college/2faa82pyl2nams3jf911n2olas33ohybjh.png)
So, the velocity of the wave is approximately 642.9 m/s.
5.
*1: Period.
*2: Crest.
*3. Trough.
*4: Amplitude.