Question

Use the quadratic formula to solve for x.2x7+72-5=0(If there is more than one solution, separate them with commas.)

Answer 1

For

`2x^2+7x-5=0`

Using the quadratic formula we get:

`\frac{-7\pm\sqrt[]{7^2-4\cdot2\cdot(-5)}}{2\cdot2}`
`\frac{-7\pm\sqrt[]{49^{}+40}}{4}`
`\frac{-7\pm\sqrt[]{89}}{4}`

So the solutions are:

`x=\frac{-7+\sqrt[]{89}}{4}`

And

`x=\frac{-7-\sqrt[]{89}}{4}`