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Use the quadratic formula to solve for x.2x7+72-5=0(If there is more than one solution, separate them with commas.)

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For


2x^2+7x-5=0

Using the quadratic formula we get:


\frac{-7\pm\sqrt[]{7^2-4\cdot2\cdot(-5)}}{2\cdot2}
\frac{-7\pm\sqrt[]{49^{}+40}}{4}
\frac{-7\pm\sqrt[]{89}}{4}

So the solutions are:


x=\frac{-7+\sqrt[]{89}}{4}

And


x=\frac{-7-\sqrt[]{89}}{4}

User DamithH
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