Question

Please show me how to do a question like this.

Answer 1

Step 1 - How specific heat relates to heat

The heat absorbed by a substance can be related to its mass (m) and temperature (delta T) variation by the following formula:

`Q=mc\Delta T`

We will use the following formula to solve the poblem.

Step 2 - Solving the exercise

According to this exercise:

`\begin{gathered} Q=2500J \\ \Delta T=350-300=50°C \\ m=347.2g \\ c=? \end{gathered}`

Setting the values in the equation:

`\begin{gathered} 2500=300*347.2* c \\ \\ c=(2500)/(104160)=0.024J/g°C \end{gathered}`

Answer: the specific heat of this metal is 0.024 J/g.°C