Given:
• Voltage, V = 550 V
,
• Current, I = 70 A
,
• Time, t = 3 hours
Let's calculate the work done by the motor.
To calculate the work done, first find the amount of energy used.
![P=I*V](https://img.qammunity.org/2023/formulas/physics/college/kpzvqj4bfi7117qcvgdtydf7s41226916y.png)
Thus, we have:
![\begin{gathered} P=70*550 \\ \\ P=38500\text{ Watts} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/nbv4by7ltd6p8b0k3p8od9whl2g515a9vy.png)
Now, to calculate the work done by the motor in 3 hours, apply the formula:
![W=P*t](https://img.qammunity.org/2023/formulas/physics/college/sachq8vjrtzewh055duizba4zb7mgdsr4c.png)
Where:
P is the power in watts = 38500 W
t is the time in seconds = 3 x 60 minutes x 60 seconds
Hence, we have:
![\begin{gathered} W=38500*3*60*60 \\ \\ W=38500*10800 \\ \\ W=415800000\text{ J} \\ \\ W=415.8*10^6\text{ J} \\ \\ W=415.8\text{ MJ} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/2utcf80a4a7ccfjsfadn046d90c0l20907.png)
Therefore, the work done by the motor is 415.8 Mega Joules.
ANSWER:
C. 415.8 MJ