Answer:
The cars travel at equal speeds at approximately
Step-by-step explanation:
Speed is the ratio of distance to time.
Let distance be y
Let time be x
and speed be s
We have;
![s=(y)/(x)](https://img.qammunity.org/2023/formulas/mathematics/college/k2s1gxjh9z23uajl8n48sgg4nc4hj1746n.png)
The car with the greatest ratio of distance to time is the one with the greatest speed.
Let us test one after the other
For x = 15, y = 12.5
![\begin{gathered} s=(12.5)/(15) \\ \\ =0.83 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/48gdv7x45odaxm4tphszd3vwy1dcpf8ji7.png)
For x = 30, y = 25
![\begin{gathered} s=(25)/(30) \\ \\ =0.83 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/5ke8x5ipa27unxrlak8vtwvq1xsuxzd4vr.png)
For x = 45, y = 37.5
![\begin{gathered} s=(37.5)/(45) \\ \\ =0.83 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/oxrf791kppgtrpsfec42lftknwturrqmh4.png)
Notice that this ratios are equal. Hence, we conclude that the cars travel at equal speeds