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Find the area of regular pentagonal arena whose side is 10 meters. Express ur answer in square feet

User Sarego
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1 Answer

4 votes

Given:

The side of a pentagonal arena is 10 meters.

The objective is to find the area of the arena in square feet.

Step-by-step explanation:

The unit of side from meter to feet can be converted as,


\begin{gathered} a=1m=10.7639\text{ fe}et \\ a=10m=107.639\text{ fe}et \end{gathered}

To find area:

The area of pentagonal arena can be calculated as,


A=(1)/(4)\sqrt[]{5(5+2\sqrt[]{5)}}* a^2\text{ . . . . . . . (1)}

Now, substitute the value of a in equation (1).


\begin{gathered} A=(1)/(4)\sqrt[]{5(5+2\sqrt[]{5)}}*(107.639)^2 \\ =\text{ }(1)/(4)(6.82)*(107.639)^2 \\ =1.72*(107.639)^2 \\ =19933.716669\ldots\ldots \\ \approx19933.72\text{ square f}eet \end{gathered}

Hence, the area of the pentagonal arena is 19933.72 square feet.

User Mario Kutlev
by
7.3k points
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