Question

What are the answers for the review I don't need anything else

Answer 1

Given,

Percentage of baskets jai make is 28%.

The number of free thorws are 120.

The number of basket likely made by jai in 120 free throws is,

`\begin{gathered} \text{Number of basket = 28\% of total fr}e\text{ throws} \\ =28\text{ \% of 120} \\ =(28)/(100)*120 \\ =33.6 \\ \approx37 \end{gathered}`

The number of basket he makes is approximately 37.

a) 1% of 120 is,

`1\text{ \% of 120 = }\frac{\text{1}}{100}*120=1.2`

b) 10% of 120 is,

`10\text{ \% of 120 = }\frac{\text{1}0}{100}*120=12`

c) 20% of 120 is,

`20\text{\% of 120 = }\frac{\text{2}0}{100}*120=24`

d) 8% of 120 is,

`8\text{\% of 120 = }\frac{\text{8}}{100}*120=9.6`