Question

The width of a golden rectangle is 10 feet. Find the area to the nearest square foot.

Answer 1

`\begin{gathered} \text{Golden rectangle} \\ (a)/(b)=\varphi\approx1.62 \\ b=10 \\ a=1.62\cdot b \\ a=16.2 \\ \text{Area = b}\cdot a \\ \text{Area =(10ft)}\cdot(16.2ft) \\ \text{Area}=162ft^2 \\ \text{The area of the golden rectangle is }162ft^2 \end{gathered}`