Question

In a certain country, the true probability of a baby being a boy is 0.519. Among the next nine randomly selected births

in the country, what is the probability that at least one of them is a girl?

Answer 1

0.9973

Explanation:

Given :

Probability of girl, probability of success , 1 - p = 1 - 0.519 = 0.481

1 - p = 0.481

n = 9

Probability that atleast one is girl

Usingbthe binomial probability distribution :

P(x =x) = nCx * p^x * (1 - p)^(n - x)

USing the binomial probability calculator :

p(x ≥ 1) = p(x=1) + p(x=2) + p(x=3) + p(x=4) + p(x=5) + p(x=6) + p(x=7) + p(x=8) + p(x=9)

p(x ≥ 1) = 0.9973 ( from calculator).