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5x2 - 23x - 10 = 0A.x = -2/5,5b. x = -10,5C.x = -2, 25Solve for x

User Seoester
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1 Answer

1 vote

5x2 - 23x - 10 = 0

A.x = -2/5,5

b. x = -10,5

C.x = -2, 25

Applying the formula of quadratic equation


x=\frac{-b\pm\sqrt[\square]{b^2-4ac}}{2a}

we have

a=5

b=-23

c=-10

substitute in the formula


\begin{gathered} x=\frac{-(-23)\pm\sqrt[\square]{(-23)^2-4(5)(-10)}}{2(5)} \\ \\ x=\frac{23\pm\sqrt[\square]{729}}{10} \\ \\ x=(23\pm27)/(10) \\ x=5 \\ x=-0.4 \end{gathered}

answer is option A

User Muhammad Ali
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