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How can (2x+y)(y+3) be drawn as a rectangle? The Length= (2x+y) The width= (y+3) Area =L x W

User Bibek
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(2x+y)(y+3) drawn as a rectangle

Length= (2x+y)

width= (y+3)

where a is a value that depends on x and y

Solution)

Apply FOIL method


\mleft(a+b\mright)\mleft(c+d\mright)=ac+ad+bc+bd
\mleft(2x+y\mright)\mleft(y+3\mright)=2xy+2x\cdot\: 3+yy+y\cdot\: 3

then, the area is


=2xy+6x+y^2+3y

we can draw this the following way

How can (2x+y)(y+3) be drawn as a rectangle? The Length= (2x+y) The width= (y+3) Area-example-1
How can (2x+y)(y+3) be drawn as a rectangle? The Length= (2x+y) The width= (y+3) Area-example-2
User MrRolling
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