Question

A wire that is 25 cm long is at right angles to a 0.30 T uniform magnetic field. The current through the wire is 6.0 A. What is the magnitude of the force on the wire?0.45 N4.5 N45 N450 N

Answer 1

F = 0.45 N

Step-by-step explanation:

The magnitude of the force on the wire can be calculated as:

`F=I\cdot L\cdot B\cdot\sin \theta`

Where I is current, L is the length of the wire, B is the magnetic field and θ is the angle formed by the wire and the magnetic field.

Since they are at a right angle, θ = 90 degrees. So, replacing I = 6.0A, L = 0.25 m = 25 cm and B = 0.30 T, we get:

`\begin{gathered} F=(6.0A)(0.25m)(0.30T)\sin 90 \\ F=0.45\text{ N} \end{gathered}`

Therefore, the magnitude of the force on the wire is 0.45 N.