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Please assist me in solving these questions. I do not know how to start these.

Please assist me in solving these questions. I do not know how to start these.-example-1

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P=-(1)/(20)x^2+5x-30

a) Use the equation above to complete the table: substitute the x in the equation by the given values in the tabe to find the corresponding value of P:


\begin{gathered} x=0 \\ P=-(1)/(20)(0)^2+5(0)-30 \\ P=-30 \\ \\ x=20 \\ P=-(1)/(20)(20)^2+5(20)-30 \\ P=-20+100-30 \\ P=50 \\ \\ x=30 \\ P=-(1)/(20)(30)^2+5(30)-30 \\ P=-(900)/(20)+150-30 \\ P=-45+150-30 \\ P=75 \end{gathered}
\begin{gathered} x=50 \\ P=-(1)/(20)(50)^2+5(50)-30 \\ P=-(2500)/(20)+250-30 \\ P=-125+250-30 \\ P=95 \\ \\ x=60 \\ P=-(1)/(20)(60)^2+5(60)-30 \\ P=-(3600)/(20)+300-30 \\ P=-180+300-30 \\ P=90 \\ \\ x=90 \\ P=-(1)/(20)(90)^2+5(90)-30 \\ P=-(8100)/(20)+450-30 \\ P=-405+450-30 \\ P=15 \end{gathered}

Table:

b) Graph:

c)

i) maximum possible profit is the maximum P in the vertex: 95

ii) the numer of glasses that need to be sold to make the maximum profit is the x value in the vertex: 50

iii) the number of glasses that need to be sold to make a profit of at least 80; x coordinate when P is 80 in the increasing part of the parabola: Approximately 33

iv) the amount of money initially invested by the three students, value of P1when x is 0: it is negative bcause is athe amount invested -30, They invested 30 Swiss Francs

d)Baljeet : Jane : Fiona

1: 2 : 3

The profit is divided into 6 parts, Baljeet receives 1/6, Jane 2/6 and Finona 3/6

If they sold 40 gasses of lemodnade the profit is 90Swiss Francs


(90)/(6)=15

1/6 of 90 is 15, as Fiona received 3/6, she has:


15*3=45

Fiona's share 45 Swiss Francs

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