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What will be the c-value in the perfect square trinomial? x^2-x+c

What will be the c-value in the perfect square trinomial? x^2-x+c-example-1

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A quadratic's general form is:


ax^2+bx+c

Our trinomial given is:


x^2-x+c

From matching it with the general form, we can say that:


\begin{gathered} a=1 \\ b=-1 \end{gathered}

For this to be a perfect square trinomial, c will take the value:


c=((b)/(2))^2^{}

We know b = -1, thus c will be:


\begin{gathered} c=((b)/(2))^2 \\ c=(-(1)/(2))^2 \\ c=(1)/(4) \end{gathered}

Thus, the value of c that will make this a perfect square trinomial:


c=(1)/(4)

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