Question

If g(x) = x^3-x+1,find a) g(0)b) g(-1) c) g(1)

Answer 1

To answer this question, we have to substitute the corresponding value of x into the function to obtain the values of the function for each given point.

Then if we have that the function is:

`g(x)=x^3-x+1`

Then we have:

For x = 0:

`\begin{gathered} g(0)=(0)^3-(0)+1 \\ g(0)=1 \end{gathered}`

For x = -1:

`\begin{gathered} g(-1)=(-1)^3-(-1)+1 \\ g(-1)=-1+1+1 \\ g(-1)=1 \end{gathered}`

For x = 1:

`\begin{gathered} g(1)=(1)^3-(1)+1 \\ g(1)=1-1+1 \\ g(1)=1 \end{gathered}`

In summary, therefore, we have that:

`\begin{gathered} g(0)=1 \\ g(-1)=1 \\ g(1)=1 \end{gathered}`