Answer:
2⅓ feet per second.
Step-by-step explanation:
10 seconds after he entered the water, the depth of the diver = 30 feet
40 seconds after he entered the water, the depth of the diver = 100 feet
The scuba diver's average rate of change
![\begin{gathered} =\frac{\text{Change in Depth}}{\text{Change in time}} \\ =(100-30)/(40-10) \\ =(70)/(30) \\ =2(1)/(3)\text{ feet per second} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/e9n5c7jh7tz3scfu5wd0b36ugux78fvf1a.png)
The scuba diver's average rate of change is 2⅓ feet per second.
In the context of this scenario, it means the scuba diver descends a depth of 2⅓ feet every second.