Answer
Account 1 $432.08
Account 2 $433.29
Account 3 $433.85
Step-by-step explanation
For Account 1
P = $2200
r = 3%
n = 6 years
Since the acoount is compounding quarterly, this implies
r = 3/4 % = 0.75% = 0.0075
A = ?
Using the compound interest formula

Therefore, the interest on Account 1 after 6 years = A - P
Interest = $2632.08 - $2200 = $432.08
For Account 2
Since the acoount is compounding monthly, this implies
r = 3/12 % = 0.25% = 0.0025

Therefore, the interest on Account 2 after 6 years = A - P
Interest = $2633.29 - $2200 = $433.29
For Account 3
Since the acoount is compounding daily, this implies
r = 3/365 % = 0.008219% = 0.00008219

Therefore, the interest on Account 3 after 6 years = A - P
Interest = $2633.85 - $2200 = $433.85