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Let f(x)=x-3 and g(x)=x+1(fg)(0)=?

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Given:

The functions given are,


\begin{gathered} f(x)=x-3 \\ g(x)=x+1 \end{gathered}

Required:

To find the value of


(fg)(0)

Step-by-step explanation:

We have two given functions as:


\begin{gathered} f(x)=x-3 \\ g(x)=x+1 \end{gathered}

Therefore, the product of two functions is given by,


\begin{gathered} (fg)(x)=f(x)\cdot g(x) \\ \Rightarrow(fg)(x)=(x-3)\cdot(x+1) \\ \Rightarrow(fg)(x)=x^2+x-3x-3 \\ \Rightarrow(fg)(x)=x^2-2x-3 \end{gathered}

Thus, the value of the product of the functions at x = 0 is,


\begin{gathered} (fg)(0)=(0)^2-2\cdot(0)-3 \\ \Rightarrow(fg)(0)=0-0-3 \\ \Rightarrow(fg)(0)=-3 \end{gathered}

Final Answer:

The value of the product of the functions at x = 0 is,


(fg)(0)=-3

User Themisterunknown
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