Question

Determine the amount (in moles) of LiNO3 needed to make 543 ml of a 1.83 M solution

Answer 1

Step-by-step explanation

Given:

Volume of the solution = 543 mL = (543/1000) = 0.543 L

Molarity of the LiNO3 solution = 1.83 M

What to find:

Amount (in moles) of LiNO3 needed to make 543 ml of a 1.83 M solution.

Solution:

The amount (in moles) of LiNO3 needed to make 543 ml of a 1.83 M solution can be determined using the molarity formula.

Hence, the amount (in moles) of LiNO3 needed to make 543 ml of a 1.83 M solution is 0.