Question:
Two truck rental companies have different rates. V-Haul has a base charge of $70.00, plus $0.50 per mile. W-Haul has a base charge of $65.60. plus $0.55 per mile. For how many miles would these two companies charge the same amount?
Solution:
First, denote by m the miles. Now, If V-Haul has a base charge of $70.00, plus $0.50 per mile, then the linear equation that describes this situation is:

On the other hand, if W-Haul has a base charge of $65.60. plus $0.55 per mile, then the linear equation that describes this situation is:

now, these companies charge the same amount when:

this is equivalent to:

this is equivalent to:

then, solving for m, we get:

then, we can conclude that the correct answer is:
if a driver drives 88 miles, those two companies would charge the same amount of money.