Answer:
Quadrilateral ABCD is not a rectangle, square, or parallelogram because both pairs of opposite sides are not parallel or congruent.
Explanation:
Consider quadrilateral ABCD with its vertices at:
A(2, 1), B(2, 4), C(7, 4), and D(6, 1).
Line AD is a horizontal line passing through y=1.
![AD=|6-2|=4\text{ units}](https://img.qammunity.org/2023/formulas/mathematics/college/gxt3eqm06szwqffg293tq3sjj5xomliosf.png)
Similarly, line BC is a horizontal line passing through y=4.
![BC=|7-2|=5\text{ units}](https://img.qammunity.org/2023/formulas/mathematics/college/dunh17ttzr5lx7zoxaq5igmzf09km57e26.png)
Since the opposite sides are not equal, the quadrilateral ABCD is not a rectangle, square, or parallelogram because both pairs of opposite sides are not parallel or congruent.
The last option is correct.
Note: The result can be confirmed from the graph below: