In general, the slope-intercept form of a linear equation is
![y=mx+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/smsb8cbft03lwblmi49nf2l6jby2ofxzws.png)
where m and b are constants.
Therefore, both y=6x+7 and y=-9x-2 are linear equations.
To find the intersection point, solve the system that consists of the two above linear equations
![\begin{cases}y=6x+7 \\ y=-9x-2\end{cases}](https://img.qammunity.org/2023/formulas/mathematics/high-school/qch352wr49165ytxwhkiqfxhgq35jwdayn.png)
Then,
![\begin{gathered} y=y \\ \Rightarrow6x+7=-9x-2 \\ \Rightarrow15x=-9 \\ \Rightarrow x=-(9)/(15)=-(3)/(5) \\ \Rightarrow x=-(3)/(5) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/naxezm3joo0wvnvr5kv7jtunay486dluu1.png)
Substitute the value of x into the first equation, as shown below,
![\begin{gathered} x=-(3)/(5) \\ \Rightarrow y=6(-(3)/(5))+7=-(18)/(5)+(35)/(5)=(17)/(5) \\ \Rightarrow y=(17)/(5) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/l6dvge175w5wsdeuk71o9xpj80vtky0of5.png)
Thus, the intersection point is (-3/5,17/5)=(-0.6,3.4)